Solution:Step 1: Identify sys.path typesys.path is a list object containing directory strings.Step 2: Check output of type()Calling type(sys.path) returns the class type of the object, which is list.Final Answer:<class 'list'> -> Option AQuick Check:sys.path is always a list [OK]

[Solved] Consider this code:import sys print(type(sys.path))What will be the output? — Ans: <class 'list'> | Python

Python - Modules and Code Organization

Consider this code:

import sys
print(type(sys.path))

What will be the output?

A<class 'list'>

B<class 'str'>

C<class 'tuple'>

DAn error will be raised

Step-by-Step Solution

Solution:

Step 1: Identify sys.path type
sys.path is a list object containing directory strings.
Step 2: Check output of type()
Calling type(sys.path) returns the class type of the object, which is list.
Final Answer:
<class 'list'> -> Option A
Quick Check:
sys.path is always a list [OK]

Quick Trick: sys.path is a list object [OK]

Common Mistakes:

Assuming sys.path is a string or tuple
Expecting an error from type() call
Confusing sys.path with sys.modules

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Consider this code:

Step 1: Identify sys.path type

Step 2: Check output of type()

Final Answer:

Quick Check:

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