[Solved] What will be the output of this code?class Parent: def message(self): print('Message from Parent') class Child(Parent): def message(self): super().message() print('Message from Child') c = Child() c.... | Python

Python - Polymorphism and Dynamic Behavior

What will be the output of this code?

class Parent:
    def message(self):
        print('Message from Parent')

class Child(Parent):
    def message(self):
        super().message()
        print('Message from Child')

c = Child()
c.message()

AMessage from Child\nMessage from Parent

BMessage from Parent\nMessage from Child

CMessage from Child

DMessage from Parent

Step-by-Step Solution

Solution:

Step 1: Call to super()
The message method in Child calls super().message(), which invokes Parent's method first.
Step 2: Subsequent print
After the parent's message prints, Child's own print statement runs.
Final Answer:
Message from Parent\nMessage from Child -> Option B
Quick Check:
super() calls parent method first [OK]

Quick Trick: super() calls parent method before child code [OK]

Common Mistakes:

MISTAKES

Assuming child message prints first
Expecting only one message printed
Ignoring super() call effect

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What will be the output of this code?

Step 1: Call to super()

Step 2: Subsequent print

Final Answer:

Quick Check:

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