[Solved] Find the error in this code that tries to write lines to a file efficiently:lines = ['line1\n', 'line2\n', 'line3\n'] file = open('output.txt', 'w') for line in lines: file.write(line) file.close() | Python

Python - File Reading and Writing Strategies

Find the error in this code that tries to write lines to a file efficiently:

lines = ['line1\n', 'line2\n', 'line3\n']
file = open('output.txt', 'w')
for line in lines:
    file.write(line)
file.close()

AUsing <code>with open()</code> is better to ensure file closes

BThe file should be opened in read mode 'r'

CThe loop should use <code>readlines()</code> instead of <code>lines</code>

DThe file is not closed properly

Step-by-Step Solution

Solution:

Step 1: Check file handling safety
Opening file without with risks leaving it open if error occurs before close().
Step 2: Use with open() for automatic closing
Replacing with with open('output.txt', 'w') as file: ensures file closes safely.
Final Answer:
Using with open() is better to ensure file closes -> Option A
Quick Check:
Use with open() to auto-close files [OK]

Quick Trick: Always use with open() to avoid forgetting file.close() [OK]

Common Mistakes:

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Find the error in this code that tries to write lines to a file efficiently: