[Solved] What will be printed when the following code is executed?class CustomError(Exception): def __init__(self, message): self.message = message try:... | Python

Python - Custom Exceptions

What will be printed when the following code is executed?

class CustomError(Exception):
    def __init__(self, message):
        self.message = message

try:
    raise CustomError('Error occurred')
except CustomError as e:
    print(e.message)

ATraceback error

BCustomError object

CNone

DError occurred

Step-by-Step Solution

Solution:

Step 1: Understand the class definition
The CustomError class stores the message in an instance variable self.message.
Step 2: Raising the exception
The exception is raised with the message 'Error occurred'.
Step 3: Catching and printing
In the except block, e.message accesses the stored message and prints it.
Final Answer:
Error occurred -> Option D
Quick Check:
Accessing exception attributes directly prints stored message [OK]

Quick Trick: Access exception attributes to get custom messages [OK]

Common Mistakes:

Printing the exception object directly without __str__ method
Assuming print(e) prints the message without overriding __str__
Not storing the message in an instance variable

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More Python Quizzes

What will be printed when the following code is executed?

Step 1: Understand the class definition

Step 2: Raising the exception

Step 3: Catching and printing

Final Answer:

Quick Check:

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