[Solved] What will be the output of this code?def f(): try: 1 / 0 except ZeroDivisionError as e: raise ValueError("Invalid value") from e try: f() except Exception as ex: print(type(ex).__name__) print(ex.... | Python

Python - Advanced Exception Handling

What will be the output of this code?

def f():
    try:
        1 / 0
    except ZeroDivisionError as e:
        raise ValueError("Invalid value") from e

try:
    f()
except Exception as ex:
    print(type(ex).__name__)
    print(ex.__cause__)

AZeroDivisionError\nNone

BValueError\nNone

CValueError\ndivision by zero

DZeroDivisionError\nValueError('Invalid value')

Step-by-Step Solution

Solution:

Step 1: Trace function f()
Inside f(), dividing by zero raises ZeroDivisionError, caught as e.
Step 2: Raise ValueError chained from ZeroDivisionError
The code raises ValueError with message "Invalid value" from e, linking the original ZeroDivisionError.
Step 3: Catch exception and print details
The outer try-except catches the ValueError, prints its type, then prints its __cause__, which is the original ZeroDivisionError.
Final Answer:
ValueError division by zero -> Option C
Quick Check:
Chained error shows new error and original cause [OK]

Quick Trick: Chained exceptions show new error and original cause [OK]

Common Mistakes:

MISTAKES

Expecting __cause__ to be None
Confusing error types printed
Missing that ValueError is raised

Master "Advanced Exception Handling" in Python

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More Python Quizzes

What will be the output of this code?

Step 1: Trace function f()

Step 2: Raise ValueError chained from ZeroDivisionError

Step 3: Catch exception and print details

Final Answer:

Quick Check:

Want More Practice?