[Solved] What will this code output?class Error(Exception): def __str__(self): return 'Custom error occurred' try: raise Error() except Error as e: print(e) | Python

Python - Custom Exceptions

What will this code output?

class Error(Exception):
    def __str__(self):
        return 'Custom error occurred'

try:
    raise Error()
except Error as e:
    print(e)

ATraceback with error message

BError

CNone

DCustom error occurred

Step-by-Step Solution

Solution:

Step 1: Understand __str__ method
The __str__ method defines the string representation of the exception instance.
Step 2: Raising and catching the exception
The exception Error is raised and caught in the except block as e.
Step 3: Printing the exception instance
Printing e calls e.__str__(), which returns 'Custom error occurred'.
Final Answer:
Custom error occurred -> Option D
Quick Check:
__str__ controls printed exception message [OK]

Quick Trick: Override __str__ to customize exception message [OK]

Common Mistakes:

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