You want to print all numbers from 0 to 5 except 3 using a loop. Which code correctly uses loop control?
hard📝 Application Q15 of 15
Python - Loop Control
You want to print all numbers from 0 to 5 except 3 using a loop. Which code correctly uses loop control?
Afor i in range(6):\n if i == 3:\n break\n print(i)
Bfor i in range(6):\n if i == 3:\n pass\n print(i)
Cfor i in range(6):\n if i != 3:\n break\n print(i)
Dfor i in range(6):\n if i == 3:\n continue\n print(i)
Step-by-Step Solution
Solution:
Step 1: Understand the goal
We want to skip printing 3 but continue printing other numbers from 0 to 5.
Step 2: Analyze each option
for i in range(6):\n if i == 3:\n break\n print(i) stops loop at 3 (break), so numbers after 3 won't print. for i in range(6):\n if i == 3:\n continue\n print(i) skips 3 (continue) and prints others. for i in range(6):\n if i != 3:\n break\n print(i) breaks when number is not 3, stopping early. for i in range(6):\n if i == 3:\n pass\n print(i) uses pass which does nothing, so 3 is printed.
Final Answer:
for i in range(6):\n if i == 3:\n continue\n print(i) -> Option D
Quick Check:
Use continue to skip unwanted values [OK]
Quick Trick:Use continue to skip, break to stop loop [OK]
Common Mistakes:
MISTAKES
Using break instead of continue to skip
Using pass thinking it skips iteration
Breaking loop too early
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