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You want to print all numbers from 0 to 5 except 3 using a loop. Which code correctly uses loop control?

hard📝 Application Q15 of 15
Python - Loop Control
You want to print all numbers from 0 to 5 except 3 using a loop. Which code correctly uses loop control?
Afor i in range(6):\n if i == 3:\n break\n print(i)
Bfor i in range(6):\n if i == 3:\n pass\n print(i)
Cfor i in range(6):\n if i != 3:\n break\n print(i)
Dfor i in range(6):\n if i == 3:\n continue\n print(i)
Step-by-Step Solution
Solution:
  1. Step 1: Understand the goal

    We want to skip printing 3 but continue printing other numbers from 0 to 5.
  2. Step 2: Analyze each option

    for i in range(6):\n if i == 3:\n break\n print(i) stops loop at 3 (break), so numbers after 3 won't print. for i in range(6):\n if i == 3:\n continue\n print(i) skips 3 (continue) and prints others. for i in range(6):\n if i != 3:\n break\n print(i) breaks when number is not 3, stopping early. for i in range(6):\n if i == 3:\n pass\n print(i) uses pass which does nothing, so 3 is printed.
  3. Final Answer:

    for i in range(6):\n if i == 3:\n continue\n print(i) -> Option D
  4. Quick Check:

    Use continue to skip unwanted values [OK]
Quick Trick: Use continue to skip, break to stop loop [OK]
Common Mistakes:
MISTAKES
  • Using break instead of continue to skip
  • Using pass thinking it skips iteration
  • Breaking loop too early

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