[Solved] Why does the following code produce an error?def func(): x = 10 print(x) — Ans: x is local to func and not accessible outside | Python

Python - Variables and Dynamic Typing

Why does the following code produce an error?

def func():
    x = 10
print(x)

Ax is local to func and not accessible outside

Bx is not assigned any value

Cprint syntax is incorrect

DNo error, prints 10

Step-by-Step Solution

Solution:

Step 1: Understand variable scope
Variable x is defined inside the function func, so it is local to that function.
Step 2: Accessing x outside function
Trying to print x outside the function causes a NameError because x is not defined in the global scope.
Final Answer:
x is local to func and not accessible outside -> Option A
Quick Check:
Local variables are not accessible outside their function [OK]

Quick Trick: Variables inside functions are local by default [OK]

Common Mistakes:

MISTAKES

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