[Solved] What will this code print?def check(num): if num > 0: print('Positive') else: print('Non-positive') check(-1) | Python

Python - Basics and Execution Environment

What will this code print?

def check(num):
    if num > 0:
        print('Positive')
    else:
        print('Non-positive')

check(-1)

APositive

BNon-positive

CNo output

DError due to indentation

Step-by-Step Solution

Solution:

Step 1: Analyze the function call
The function check is called with -1, which is not greater than 0.
Step 2: Follow the if-else logic
Since -1 is not > 0, the else block runs, printing 'Non-positive'.
Final Answer:
Non-positive -> Option B
Quick Check:
Indentation defines if-else blocks correctly [OK]

Quick Trick: Indent else at same level as if [OK]

Common Mistakes:

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