[Solved] Find the error in this code snippet:for i in range(4): if i == 2: continue print(i) break — Ans: The break is inside the loop and will stop after first iteration | Python

Python - Loop Control

Find the error in this code snippet:

for i in range(4):
    if i == 2:
        continue
    print(i)
    break

AThe break is inside the loop and will stop after first iteration

Bcontinue is used incorrectly and causes syntax error

CThe loop will never run because of break before print

DNo error, code runs and prints 0, 1, 3

Step-by-Step Solution

Solution:

Step 1: Understand loop flow with continue and break
When i == 2, continue skips print and break for that iteration. For other values, print runs then break stops loop immediately.
Step 2: Identify effect of break placement
Break inside the loop after print causes loop to stop after first printed value, so only one value prints.
Final Answer:
The break is inside the loop and will stop after first iteration -> Option A
Quick Check:
Break stops loop early due to placement [OK]

Quick Trick: Break after print stops loop early, continue skips iteration [OK]

Common Mistakes:

MISTAKES

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