[Solved] What will be the output of this PowerShell code? $session = New-PSSession -ComputerName localhost Invoke-Command -Session $session -ScriptBlock {... What will be the output of this PowerShell code? | PowerShell

PowerShell - Remote Management

What will be the output of this PowerShell code?

 $session = New-PSSession -ComputerName localhost
Invoke-Command -Session $session -ScriptBlock { Get-Process | Select-Object -First 1 }
Remove-PSSession -Session $session

ADisplays the first process running on the local computer

BCreates a session but does not display any output

CThrows an error because Remove-PSSession is called too early

DDisplays all processes running on the local computer

Step-by-Step Solution

Solution:

Step 1: Understand the commands
The code creates a session to localhost, runs a command to get the first process, then removes the session.
Step 2: Analyze the Invoke-Command output
The Invoke-Command runs Get-Process | Select-Object -First 1 remotely, so it outputs the first process object.
Final Answer:
Displays the first process running on the local computer -> Option A
Quick Check:
Invoke-Command outputs first process [OK]

Quick Trick: Invoke-Command outputs scriptblock result before Remove-PSSession [OK]

Common Mistakes:

Thinking Remove-PSSession stops output
Assuming no output from Invoke-Command
Confusing output with all processes

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What will be the output of this PowerShell code?

Step 1: Understand the commands

Step 2: Analyze the Invoke-Command output

Final Answer:

Quick Check:

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