[Solved] What will be the output of this PowerShell code?try { Get-Item 'C:\missing.txt' } catch { Add-Content -Path 'error.log' -Value "Error: $_"; 'Error logged' } | PowerShell

PowerShell - Error Handling

What will be the output of this PowerShell code?

try { Get-Item 'C:\missing.txt' } catch { Add-Content -Path 'error.log' -Value "Error: $_"; 'Error logged' }

AThe script crashes with an error

BNo output, error is suppressed

CError logged

DThe content of 'missing.txt' is displayed

Step-by-Step Solution

Solution:

Step 1: Analyze try-catch behavior
Get-Item fails, triggering catch block which logs error and returns 'Error logged'.
Step 2: Understand output from catch block
The catch block outputs the string 'Error logged' after writing to the log file.
Final Answer:
Error logged -> Option C
Quick Check:
Catch block output = 'Error logged' [OK]

Quick Trick: Catch block output is returned after logging error [OK]

Common Mistakes:

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