[Solved] What will be the output of this PowerShell code? $obj = New-Object PSObject -Property @{Name='Alice'} $obj | Add-Member -MemberType ScriptMethod... What will be the output of this PowerShell code? | PowerShell

PowerShell - Working with Objects

What will be the output of this PowerShell code?

$obj = New-Object PSObject -Property @{Name='Alice'}
$obj | Add-Member -MemberType ScriptMethod -Name SayName -Value { "My name is $($this.Name)" }
$obj.SayName()

AMy name is

BMy name is $this.Name

CMy name is Alice

DError: Property 'Name' not found

Step-by-Step Solution

Solution:

Step 1: Understand object and method
$obj has a property Name='Alice'. The ScriptMethod SayName uses $this.Name to access that property.
Step 2: Evaluate method call output
Calling $obj.SayName() runs the script block, replacing $($this.Name) with 'Alice', so output is 'My name is Alice'.
Final Answer:
My name is Alice -> Option C
Quick Check:
$this.Name accesses property correctly [OK]

Quick Trick: Use $this to access object properties inside ScriptMethod [OK]

Common Mistakes:

Expecting literal $this.Name output
Confusing property access syntax
Thinking method won't access object properties

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What will be the output of this PowerShell code?

Step 1: Understand object and method

Step 2: Evaluate method call output

Final Answer:

Quick Check:

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