[Solved] What will this PowerShell code output?for ($i = 1; $i -le 3; $i++) { if ($i -eq 2) { continue } Write-Output $i } | PowerShell

PowerShell - Control Flow

What will this PowerShell code output?

for ($i = 1; $i -le 3; $i++) { if ($i -eq 2) { continue } Write-Output $i }

A1

B1 2 3

C2 3

D1 3

Step-by-Step Solution

Solution:

Step 1: Understand the loop and continue
The loop runs $i from 1 to 3. When $i equals 2, 'continue' skips the rest of that iteration.
Step 2: Trace output values
Output occurs only when $i is not 2, so outputs are 1 and 3.
Final Answer:
1 3 -> Option D
Quick Check:
continue skips 2, outputs 1 and 3 [OK]

Quick Trick: continue skips current loop step, so that value is not output [OK]

Common Mistakes:

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