[Solved] Why does the following PowerShell code output only a single element?$arr = @(1, 2, 3)$arr = $arr[1]Write-Output $arr | PowerShell

PowerShell - Variables and Data Types

Why does the following PowerShell code output only a single element?

$arr = @(1, 2, 3)
$arr = $arr[1]
Write-Output $arr

AArrays cannot be reassigned in PowerShell

B$arr[1] returns a single element, replacing the array

CWrite-Output only prints the last element by default

DThe array is empty after assignment

Step-by-Step Solution

Solution:

Step 1: Understand array element access
$arr[1] accesses the second element, which is a single value, not an array.
Step 2: Assignment replaces the array with that single element
Assigning $arr = $arr[1] replaces the entire array with just the element at index 1.
Final Answer:
$arr[1] returns a single element, replacing the array -> Option B
Quick Check:
Array element access returns single value [OK]

Quick Trick: Accessing element returns single value, not array [OK]

Common Mistakes:

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