[Solved] You wrote this code inside a PostgreSQL function:RAISE EXCEPTION 'Error: %', message;But it causes an error: "ERROR: column "message" does not exist". What is the likely problem? | PostgreSQL

PostgreSQL - PL/pgSQL Fundamentals

You wrote this code inside a PostgreSQL function:

RAISE EXCEPTION 'Error: %', message;

But it causes an error: "ERROR: column "message" does not exist". What is the likely problem?

AThe variable 'message' is not declared or out of scope.

BRAISE EXCEPTION cannot use placeholders like '%'.

CYou must use RAISE WARNING instead of EXCEPTION for variables.

DThe syntax requires double quotes around 'message'.

Step-by-Step Solution

Solution:

Step 1: Understand the error message
The error says column "message" does not exist, meaning 'message' is treated as a column or variable but is undefined.
Step 2: Check variable declaration and scope
In PL/pgSQL, variables must be declared before use. If 'message' is not declared or out of scope, this error occurs.
Final Answer:
The variable 'message' is not declared or out of scope. -> Option A
Quick Check:
Undefined variable causes this error [OK]

Quick Trick: Declare variables before using in RAISE [OK]

Common Mistakes:

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You wrote this code inside a PostgreSQL function: