[Solved] CREATE TABLE logs_2023 PARTITION OF logs FOR VALUES FROM ('2023-01-01') TO ('2024-01-01');Which error will occur if you run this?INSERT INTO logs (log_date) VALUES ('2022-12-31'); | PostgreSQL

PostgreSQL - Table Partitioning

You have this partitioned table:

CREATE TABLE logs (id SERIAL, log_date DATE) PARTITION BY RANGE (log_date);
CREATE TABLE logs_2023 PARTITION OF logs FOR VALUES FROM ('2023-01-01') TO ('2024-01-01');

Which error will occur if you run this?

INSERT INTO logs (log_date) VALUES ('2022-12-31');

AERROR: syntax error near VALUES

BERROR: no partition found for row

CThe row is inserted into logs_2023 partition

DThe row is inserted into a default partition automatically

Step-by-Step Solution

Solution:

Step 1: Check partition ranges
logs_2023 covers dates from 2023-01-01 to 2024-01-01 only.
Step 2: Insert date outside partition range
2022-12-31 is before 2023-01-01, so no matching partition exists.
Final Answer:
ERROR: no partition found for row -> Option B
Quick Check:
Insert outside range = no partition error [OK]

Quick Trick: Insert date must fit partition range or error occurs [OK]

Common Mistakes:

Expecting automatic default partition
Thinking syntax error occurs
Assuming row goes to nearest partition

Master "Table Partitioning" in PostgreSQL

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You have this partitioned table:

Step 1: Check partition ranges

Step 2: Insert date outside partition range

Final Answer:

Quick Check:

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