[Solved] Identify the problem in this PHP code snippet:class User {} class Admin extends User {} function login(Admin $a) { echo "Admin logged in"; } $user = new User(); login($user); | PHP

PHP - Inheritance and Polymorphism

Identify the problem in this PHP code snippet:

class User {}
class Admin extends User {}

function login(Admin $a) {
    echo "Admin logged in";
}

$user = new User();
login($user);

APassing a User object to a function expecting Admin causes a type error.

BThe function should accept User instead of Admin to avoid errors.

CThere is no problem; User is a parent of Admin.

DThe class Admin must extend another class to work.

Step-by-Step Solution

Solution:

Step 1: Understand type hinting
The function expects an Admin object.
Step 2: Analyze argument
The argument is a User object, which is a parent class, not a subclass.
Step 3: Result
PHP does not allow passing a parent class object where a subclass is expected, causing a TypeError.
Final Answer:
Passing a User object to a function expecting Admin causes a type error. -> Option A
Quick Check:
Subclass type hint requires subclass object [OK]

Quick Trick: Subclass hint requires subclass object [OK]

Common Mistakes:

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