[Solved] What will this code output?try { echo "X "; throw new Exception("Error"); } catch (Exception $e) { echo "Y "; throw new Exception("New Error"); } finally { echo "Z "; } | PHP

PHP - Error and Exception Handling

What will this code output?

try {
    echo "X ";
    throw new Exception("Error");
} catch (Exception $e) {
    echo "Y ";
    throw new Exception("New Error");
} finally {
    echo "Z ";
}

AX Y Z and then fatal error

BX Y Z

CX Z

DX Y

Step-by-Step Solution

Solution:

Step 1: Execute try block
Prints "X ", then throws Exception.
Step 2: catch block runs, prints "Y ", then throws new Exception
This new exception is not caught inside this block.
Step 3: finally block runs, prints "Z "
After finally, uncaught exception causes fatal error.
Final Answer:
Output is "X Y Z " followed by fatal error. -> Option A
Quick Check:
New exception thrown in catch triggers fatal error after finally [OK]

Quick Trick: Exception thrown in catch triggers fatal error after finally [OK]

Common Mistakes:

Assuming new exception is caught automatically
Ignoring finally output
Thinking code stops before finally

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More PHP Quizzes

What will this code output?

Step 1: Execute `try` block

Step 2: `catch` block runs, prints "Y ", then throws new Exception

Step 3: `finally` block runs, prints "Z "

Final Answer:

Quick Check:

Want More Practice?

What will this code output?

Step 1: Execute try block

Step 2: catch block runs, prints "Y ", then throws new Exception

Step 3: finally block runs, prints "Z "

Final Answer:

Quick Check:

Want More Practice?

Step 1: Execute `try` block

Step 2: `catch` block runs, prints "Y ", then throws new Exception

Step 3: `finally` block runs, prints "Z "