[Solved] What will be the output of this PHP code?try { echo "Start\n"; throw new Exception("Error happened"); echo "End\n"; } catch (Exception $e) { echo "Caught: " . $e->getMessage() . "\n"; } echo "Done\n"; | PHP

PHP - Error and Exception Handling

What will be the output of this PHP code?

try {
    echo "Start\n";
    throw new Exception("Error happened");
    echo "End\n";
} catch (Exception $e) {
    echo "Caught: " . $e->getMessage() . "\n";
}
echo "Done\n";

AStart Caught: Error happened Done

BStart Done

CCaught: Error happened Done

DStart End Caught: Error happened Done

Step-by-Step Solution

Solution:

Step 1: Trace code inside try block
"Start" is printed, then an Exception is thrown, so the next echo "End" is skipped.
Step 2: Catch block runs and prints message
The catch block prints "Caught: Error happened" and then after try-catch, "Done" is printed.
Final Answer:
Start Caught: Error happened Done -> Option A
Quick Check:
Exception stops try, catch prints message, then Done [OK]

Quick Trick: Exception skips rest of try, catch runs, then code continues [OK]

Common Mistakes:

Thinking code after throw runs
Missing catch block output
Assuming program stops after exception

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More PHP Quizzes

What will be the output of this PHP code?

Step 1: Trace code inside try block

Step 2: Catch block runs and prints message

Final Answer:

Quick Check:

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