[Solved] What will be the output of this PHP code?class Animal { private $type = 'Dog'; public function getType() { return $this->type; } } $animal = new Animal(); echo $animal->type; | PHP

PHP - Classes and Objects

What will be the output of this PHP code?

class Animal {
  private $type = 'Dog';
  public function getType() {
    return $this->type;
  }
}
$animal = new Animal();
echo $animal->type;

AError: Cannot access private property

Bnull

CDog

DFatal error: Undefined property

Step-by-Step Solution

Solution:

Step 1: Identify property visibility and access
The property $type is private, so it cannot be accessed directly outside the class.
Step 2: Analyze the direct property access
Accessing $animal->type directly causes an error because private properties are inaccessible outside the class.
Final Answer:
Error: Cannot access private property -> Option A
Quick Check:
Direct access to private property = error [OK]

Quick Trick: Private properties cannot be accessed directly outside the class [OK]

Common Mistakes:

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