[Solved] What is wrong with this PHP code?$data = ['x' => 10, 'y' => 20];$json = json_encode($data);$arr = json_decode($json, false);echo $arr['x']; | PHP

PHP - File Handling

What is wrong with this PHP code?

$data = ['x' => 10, 'y' => 20];
$json = json_encode($data);
$arr = json_decode($json, false);
echo $arr['x'];

Aecho cannot print decoded JSON

Bjson_encode cannot encode associative arrays

Cjson_decode with false returns object, cannot use [] to access

Djson_decode second argument must be omitted for object

Step-by-Step Solution

Solution:

Step 1: Understand json_decode second argument
Passing false returns an object, not an array.
Step 2: Accessing object properties
Using [] on an object causes error; must use ->.
Final Answer:
json_decode with false returns object, cannot use [] to access -> Option C
Quick Check:
Use -> for object, [] for array after json_decode [OK]

Quick Trick: false or omitted returns object; true returns array [OK]

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