[Solved] What is wrong with this PHP code snippet?class Test {} $instance = new Test(); if (Test instanceof $instance) { echo 'Valid'; } | PHP

PHP - Inheritance and Polymorphism

What is wrong with this PHP code snippet?

class Test {}
$instance = new Test();
if (Test instanceof $instance) {
    echo 'Valid';
}

AThe <code>instanceof</code> operator expects an object on the left and a class name or object on the right.

BThe class <code>Test</code> is not defined properly.

CThe <code>instanceof</code> operator cannot be used with variables.

DThe <code>echo</code> statement is invalid inside the if block.

Step-by-Step Solution

Solution:

Step 1: Analyze the operands of instanceof
The left operand must be an object, and the right operand must be a class name string or an object.
Step 2: Identify the error
Here, Test is a class name, not an object, so using it on the left side is incorrect.
Final Answer:
The code is invalid because Test instanceof $instance uses a class name on the left side instead of an object. -> Option A
Quick Check:
Left operand must be an object [OK]

Quick Trick: Left side of instanceof must be an object [OK]

Common Mistakes:

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What is wrong with this PHP code snippet?