[Solved] Analyze this PHP code:<?php session_start(); if (!isset($_SESSION['visits'])) { $_SESSION['visits'] = 1; } else { $_SESSION['visits'] += 1;... ?>What will be displayed on the fourth page load? | PHP

PHP - Sessions and Cookies

Analyze this PHP code:

<?php
session_start();
if (!isset($_SESSION['visits'])) {
  $_SESSION['visits'] = 1;
} else {
  $_SESSION['visits'] += 1;
}
echo $_SESSION['visits'];
?>

What will be displayed on the fourth page load?

A4

B3

C1

DUndefined index error

Step-by-Step Solution

Solution:

Step 1: Start the session
session_start() resumes the session to access stored variables.
Step 2: Check if 'visits' is set
On the first load, $_SESSION['visits'] is not set, so it is initialized to 1.
Step 3: Increment on subsequent loads
On each following load, the value increments by 1.
Step 4: Calculate value on fourth load
Loads: 1st = 1, 2nd = 2, 3rd = 3, 4th = 4.
Final Answer:
4 -> Option A
Quick Check:
Session variable increments correctly each load [OK]

Quick Trick: Session variables persist and increment across page loads [OK]

Common Mistakes:

Not calling session_start() before accessing session variables
Resetting session variables on each load
Miscounting the number of increments

Master "Sessions and Cookies" in PHP

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More PHP Quizzes

Analyze this PHP code:

Step 1: Start the session

Step 2: Check if 'visits' is set

Step 3: Increment on subsequent loads

Step 4: Calculate value on fourth load

Final Answer:

Quick Check:

Want More Practice?