[Solved] Identify the error in this PHP form handling snippet: <?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { $email = $_POST['email']; } echo "Email: $email"; ?> | PHP

PHP - Superglobals and Web Context

Identify the error in this PHP form handling snippet:

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $email = $_POST['email'];
}
echo "Email: $email";
?>

AEchoing variable outside the if block without initialization

BUsing $_POST without checking if 'email' exists

CMissing semicolon after echo statement

DIncorrect request method check

Step-by-Step Solution

Solution:

Step 1: Analyze variable scope and initialization
The variable $email is assigned only inside the if block, so if the request method is not POST, it remains undefined.
Step 2: Check usage of variable outside if block
Echoing $email outside the if block without initialization causes a notice or error if the form is not submitted.
Final Answer:
Echoing variable outside the if block without initialization -> Option A
Quick Check:
Use variable only after initialization [OK]

Quick Trick: Initialize variables before use outside condition [OK]

Common Mistakes:

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