[Solved] What will be the output of the following PHP code?$dir = 'testdir'; if (is_dir($dir)) { echo 'Directory exists'; } else { echo 'Directory does not exist'; }Assuming testdir exists as a directory. | PHP

PHP - File Handling

What will be the output of the following PHP code?

$dir = 'testdir';
if (is_dir($dir)) {
  echo 'Directory exists';
} else {
  echo 'Directory does not exist';
}

Assuming testdir exists as a directory.

ADirectory exists

BDirectory does not exist

CError: Undefined variable

DNo output

Step-by-Step Solution

Solution:

Step 1: Check if the directory exists using is_dir()
Since 'testdir' exists as a directory, is_dir($dir) returns true.
Step 2: Determine the output based on the condition
The if condition is true, so it echoes 'Directory exists'.
Final Answer:
Directory exists -> Option A
Quick Check:
Directory check true = 'Directory exists' [OK]

Quick Trick: is_dir() returns true if directory exists [OK]

Common Mistakes:

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