[Solved] Find the error in this PHP snippet:$value = 10;$Value = 20;echo $value; — Ans: PHP variables are case-sensitive, so $value and $Value are different | PHP

PHP - Variables and Data Types

Find the error in this PHP snippet:

$value = 10;
$Value = 20;
echo $value;

APHP variables are case-sensitive, so $value and $Value are different

BVariable names cannot start with uppercase letters

CCannot assign two different values to variables

Decho cannot print variables with uppercase letters

Step-by-Step Solution

Solution:

Step 1: Understand PHP variable case sensitivity
PHP treats $value and $Value as two different variables.
Step 2: Analyze the echo statement
echo $value prints 10, ignoring $Value which is 20.
Final Answer:
PHP variables are case-sensitive, so $value and $Value are different -> Option A
Quick Check:
PHP variable names are case-sensitive [OK]

Quick Trick: Variable names in PHP are case-sensitive [OK]

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