PHP - Variables and Data Types
What will be the output of this PHP code?
$age = 25;
$age = $age + 5;
echo $age;
What will be the output of this PHP code?
medium📝 Predict Output Q13 of 15
Step-by-Step Solution
Solution:
Step 1: Understand variable assignment and update
$age starts at 25, then 5 is added and stored back in $age.Step 2: Calculate the new value
25 + 5 = 30, so $age becomes 30.Final Answer:
30 -> Option DQuick Check:
25 + 5 = 30 [OK]
Quick Trick: Adding to variable updates its value [OK]
Common Mistakes:
- Expecting original value without addition
- Confusing assignment with comparison
- Thinking echo prints variable name
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