[Solved] Identify the error in this PHP code snippet:$1var = 100;echo $1var; — Ans: Variable names cannot start with a number | PHP

PHP - Variables and Data Types

Identify the error in this PHP code snippet:

$1var = 100;
echo $1var;

AVariable names cannot contain letters

BMissing semicolon after assignment

CDollar sign ($) is missing

DVariable names cannot start with a number

Step-by-Step Solution

Solution:

Step 1: Check variable naming rules
PHP variable names must start with a letter or underscore, not a number.
Step 2: Analyze the code
$1var starts with a number '1', which is invalid.
Final Answer:
Variable names cannot start with a number -> Option D
Quick Check:
Variable name rules = start with letter or _ [OK]

Quick Trick: Variable names must start with letter or underscore [OK]

Common Mistakes:

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