[Solved] What is wrong with this PHP code?$num = '10';if ($num = 10) { echo 'Matched';} — Ans: Assignment used instead of comparison in if condition | PHP

PHP - Type Handling

What is wrong with this PHP code?

$num = '10';
if ($num = 10) {
    echo 'Matched';
}

AVariable $num is not declared

BAssignment used instead of comparison in if condition

CMissing semicolon after echo statement

DUsing double quotes instead of single quotes

Step-by-Step Solution

Solution:

Step 1: Analyze the if condition
The condition if ($num = 10) assigns 10 to $num instead of comparing it.
Step 2: Identify correct comparison operator
Comparison requires == or ===, not = which is assignment.
Final Answer:
Assignment used instead of comparison in if condition -> Option B
Quick Check:
Use == or === for comparison, not = [OK]

Quick Trick: Use == or === in conditions, not = [OK]

Common Mistakes:

Master "Type Handling" in PHP

9 interactive learning modes - each teaches the same concept differently

More PHP Quizzes

What is wrong with this PHP code?