[Solved] Identify the error in this PHP code snippet: echo "Path to file: C:\newfolder\file.txt"; — Ans: Backslashes are not escaped, causing incorrect output | PHP

PHP - Output and String Handling

Identify the error in this PHP code snippet:

echo "Path to file: C:\newfolder\file.txt";

ADouble quotes inside string are not escaped

BBackslashes are not escaped, causing incorrect output

CSingle quotes should be used instead of double quotes

DNo error, code runs correctly

Step-by-Step Solution

Solution:

Step 1: Analyze backslash usage in double-quoted strings
In PHP, backslash (\) is an escape character. To print a literal backslash, you must escape it as \\.
Step 2: Check the given string for backslash escaping
The string uses single backslashes before 'n' and 'f', which PHP interprets as escape sequences (\n = newline, \f = form feed). This changes the output unexpectedly.
Final Answer:
Backslashes are not escaped, causing incorrect output -> Option B
Quick Check:
Escape backslash as \\ to print it literally [OK]

Quick Trick: Escape backslash as \\ inside double quotes [OK]

Common Mistakes:

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