[Solved] What will be the output of this PHP code?<?php $score = 75; if ($score >= 90) { echo "Grade A"; } elseif ($score >= 80) { echo "Grade B"; } elseif ($score >= 70) { echo "Grade C";... | PHP

PHP - Conditional Statements

What will be the output of this PHP code?

<?php
$score = 75;
if ($score >= 90) {
    echo "Grade A";
} elseif ($score >= 80) {
    echo "Grade B";
} elseif ($score >= 70) {
    echo "Grade C";
} else {
    echo "Grade F";
}
?>

AGrade A

BGrade F

CGrade B

DGrade C

Step-by-Step Solution

Solution:

Step 1: Check conditions in order
Score is 75. First condition (>=90) is false, second (>=80) false, third (>=70) true.
Step 2: Determine executed block
Since third condition is true, it prints "Grade C" and skips else.
Final Answer:
Grade C -> Option D
Quick Check:
75 >= 70 = Grade C [OK]

Quick Trick: Check conditions top to bottom, first true runs [OK]

Common Mistakes:

Choosing Grade B or A incorrectly
Ignoring elseif order
Assuming else runs always

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What will be the output of this PHP code?

Step 1: Check conditions in order

Step 2: Determine executed block

Final Answer:

Quick Check:

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