You have a 3D numpy array data with shape (4, 3, 2). How do you access the single element in the 4th block, 2nd row, and 1st column?

hard📝 Application Q15 of 15

NumPy - Indexing and Slicing

You have a 3D numpy array data with shape (4, 3, 2). How do you access the single element in the 4th block, 2nd row, and 1st column?

Adata[3, 1, 0]

Bdata[4, 2, 1]

Cdata[3][1][1]

Ddata[2, 1, 0]

Step-by-Step Solution

Solution:

Step 1: Understand zero-based indexing for 3D arrays
4th block means index 3, 2nd row means index 1, 1st column means index 0.
Step 2: Write the correct index tuple
Use data[3, 1, 0] to access the element.
Final Answer:
data[3, 1, 0] -> Option A
Quick Check:
3D array access = data[3,1,0] [OK]

Quick Trick: Count from zero for each dimension in order [OK]

Common Mistakes:

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