Given a numpy array data = np.array([1, 2, 3, 4, 5]), which code snippet correctly computes the variance and then the standard deviation using that variance?

hard📝 Application Q9 of 15

NumPy - Aggregation Functions

Given a numpy array data = np.array([1, 2, 3, 4, 5]), which code snippet correctly computes the variance and then the standard deviation using that variance?

Avar = np.var(data); std = np.sqrt(var)

Bstd = np.var(data); var = np.sqrt(std)

Cvar = np.std(data); std = np.sqrt(var)

Dstd = np.std(data); var = std ** 2

Step-by-Step Solution

Solution:

Step 1: Calculate variance first
Variance is calculated with np.var(data).
Step 2: Calculate std as square root of variance
Standard deviation = sqrt(variance) using np.sqrt(var).
Final Answer:
var = np.var(data); std = np.sqrt(var) -> Option A
Quick Check:
Std = sqrt(variance) [OK]

Quick Trick: Std deviation is square root of variance [OK]

Common Mistakes:

Swapping std and var
Taking sqrt of std
Using std instead of var for sqrt

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More NumPy Quizzes

Given a numpy array data = np.array([1, 2, 3, 4, 5]), which code snippet correctly computes the variance and then the standard deviation using that variance?

Step 1: Calculate variance first

Step 2: Calculate std as square root of variance

Final Answer:

Quick Check:

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