[Solved] The code below is intended to print the standard deviation of data. What is wrong?import numpy as np data = [1, 2, 3, 4, 5] print(np.std(data, ddof=1)) | NumPy

NumPy - Aggregation Functions

The code below is intended to print the standard deviation of data. What is wrong?

import numpy as np
data = [1, 2, 3, 4, 5]
print(np.std(data, ddof=1))

ANothing is wrong; code runs correctly

B<code>ddof</code> is not a valid argument for <code>np.std()</code>

CThe code will raise a TypeError because <code>data</code> is a list, not an array

DThe code calculates variance, not standard deviation

Step-by-Step Solution

Solution:

Step 1: Check if ddof is valid for np.std()
The ddof parameter (delta degrees of freedom) is valid for np.std() and adjusts divisor for sample standard deviation.
Step 2: Check if input type is acceptable
np.std() accepts lists and converts them internally to arrays, so no error occurs.
Final Answer:
Nothing is wrong; code runs correctly -> Option A
Quick Check:
ddof works with np.std() and lists accepted [OK]

Quick Trick: ddof works with np.std() for sample std [OK]

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The code below is intended to print the standard deviation of data. What is wrong?