[Solved] What will be the output of this code?import numpy as np print(np.eye(2, 3, k=-1)) — Ans: [[0. 0. 0.] [1. 0. 0.]] | NumPy

NumPy - Creating Arrays

What will be the output of this code?

import numpy as np
print(np.eye(2, 3, k=-1))

A[[0. 1. 0.] [0. 0. 1.]]

B[[0. 0. 0.] [0. 1. 0.]]

C[[0. 0. 0.] [1. 0. 0.]]

D[[1. 0. 0.] [0. 0. 0.]]

Step-by-Step Solution

Solution:

Step 1: Understand np.eye(2,3,k=-1)
This creates a 2x3 matrix with ones on the diagonal shifted one below the main diagonal.
Step 2: Place ones accordingly
First row has zeros, second row has 1 at column 0 (one below main diagonal).
Final Answer:
[[0. 0. 0.] [1. 0. 0.]] -> Option C
Quick Check:
Negative k shifts diagonal down [OK]

Quick Trick: Negative k shifts diagonal down by k rows [OK]

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