[Solved] What will be the shape of the array after executing the following code?import numpy as np arr = np.array([[[5], [6], [7]]]) squeezed_arr = np.squeeze(arr) | NumPy

NumPy - Array Manipulation

What will be the shape of the array after executing the following code?

import numpy as np
arr = np.array([[[5], [6], [7]]])
squeezed_arr = np.squeeze(arr)

A(1, 3, 1)

B(1, 3)

C(3, 1)

D(3,)

Step-by-Step Solution

Solution:

Step 1: Initial shape
The array arr has shape (1, 3, 1).
Step 2: Applying np.squeeze()
Removes all axes of length 1, so axes 0 and 2 are removed.
Step 3: Resulting shape
After squeezing, the shape becomes (3,).
Final Answer:
(3,) -> Option D
Quick Check:
All singleton dimensions removed [OK]

Quick Trick: np.squeeze removes all dimensions of size 1 [OK]

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