[Solved] Given two NumPy arrays:a = np.array([1, 0, 3, 0, 5]) b = np.array([0, 2, 3, 4, 0])Which code snippet correctly creates a boolean array that is True where a is non-zero AND b is zero? | NumPy

NumPy - Array Operations

Given two NumPy arrays:

a = np.array([1, 0, 3, 0, 5])
b = np.array([0, 2, 3, 4, 0])

Which code snippet correctly creates a boolean array that is True where a is non-zero AND b is zero?

Anp.logical_and(a != 0, b == 0)

Bnp.logical_or(a != 0, b == 0)

Cnp.logical_not(np.logical_and(a == 0, b != 0))

Dnp.logical_and(a == 0, b == 0)

Step-by-Step Solution

Solution:

Step 1: Translate the condition into logical expressions
We want True where a is not zero AND b is zero, so conditions are a != 0 and b == 0.
Step 2: Use numpy.logical_and to combine conditions element-wise
np.logical_and(a != 0, b == 0) returns True only where both conditions hold.
Final Answer:
np.logical_and(a != 0, b == 0) -> Option A
Quick Check:
AND of (a != 0) and (b == 0) = np.logical_and(a != 0, b == 0) [OK]

Quick Trick: Combine conditions with logical_and for AND filtering [OK]

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