[Solved] What will be logged to the console when running this code?let count = 0;setTimeout(() => { count += 5; console.log(count);}, 0);console.log(count); | Node.js

Node.js - Debugging and Profiling

What will be logged to the console when running this code?

let count = 0;
setTimeout(() => {
  count += 5;
  console.log(count);
}, 0);
console.log(count);

A0 then 5

B5 then 0

C5 then 5

D0 then 0

Step-by-Step Solution

Solution:

Step 1: Understand setTimeout behavior
setTimeout with 0 delay runs after the current code finishes, so console.log(count) outside runs first.
Step 2: Trace the output order
First console.log prints 0, then after timeout callback runs, it prints 5.
Final Answer:
0 then 5 -> Option A
Quick Check:
Async setTimeout logs = 0 then 5 [OK]

Quick Trick: setTimeout runs after current code, so logs delayed [OK]

Common Mistakes:

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