Solution:Step 1: Understand JSON.parse behaviorParsing invalid JSON throws a SyntaxError synchronously.Step 2: Catch block handles the errorThe catch block prints the error name, which is 'SyntaxError'.Final Answer:Error: SyntaxError -> Option CQuick Check:JSON.parse error caught = A [OK]

[Solved] Consider this code:try { JSON.parse('invalid'); console.log('Parsed'); } catch (err) { console.log('Error:', err.name); }What will be printed? | Node.js

Node.js - Error Handling Patterns

Consider this code:

try {
  JSON.parse('invalid');
  console.log('Parsed');
} catch (err) {
  console.log('Error:', err.name);
}

What will be printed?

AError: ReferenceError

BParsed

CError: SyntaxError

DNothing, program crashes

Step-by-Step Solution

Solution:

Step 1: Understand JSON.parse behavior
Parsing invalid JSON throws a SyntaxError synchronously.
Step 2: Catch block handles the error
The catch block prints the error name, which is 'SyntaxError'.
Final Answer:
Error: SyntaxError -> Option C
Quick Check:
JSON.parse error caught = A [OK]

Quick Trick: Invalid JSON throws SyntaxError caught by catch [OK]

Common Mistakes:

Expecting 'Parsed' to print
Confusing error types
Assuming program crashes without catch

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More Node.js Quizzes

Consider this code:

Step 1: Understand JSON.parse behavior

Step 2: Catch block handles the error

Final Answer:

Quick Check:

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