[Solved] What will be the output order of the following code? console.log('start'); process.nextTick(() => console.log('nextTick')); setImmediate(() => console.log('setImmediate')); console.log('end'); | Node.js

Node.js - Timers and Scheduling

What will be the output order of the following code?

console.log('start');
process.nextTick(() => console.log('nextTick'));
setImmediate(() => console.log('setImmediate'));
console.log('end');

Astart\nsetImmediate\nnextTick\nend

Bstart\nend\nnextTick\nsetImmediate

Cstart\nnextTick\nend\nsetImmediate

DnextTick\nstart\nend\nsetImmediate

Step-by-Step Solution

Solution:

Step 1: Identify synchronous and asynchronous calls
console.log('start') and console.log('end') run immediately in order. process.nextTick runs after current operation but before I/O. setImmediate runs after I/O.
Step 2: Determine execution order
Output order is: 'start' (sync), 'end' (sync), 'nextTick' (nextTick queue), then 'setImmediate' (next event loop cycle).
Final Answer:
start\nend\nnextTick\nsetImmediate -> Option B
Quick Check:
nextTick before setImmediate, sync logs first [OK]

Quick Trick: Sync logs first, nextTick before setImmediate [OK]

Common Mistakes:

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