Bird
0
0

Given this code snippet with debugger statements:

medium📝 component behavior Q13 of 15
Node.js - Debugging and Profiling
Given this code snippet with debugger statements:
function add(a, b) {
  debugger;
  return a + b;
}

console.log(add(2, 3));

What happens when you run node inspect script.js on this file?
AThe program runs without pausing and prints 5 immediately
BThe program crashes with an exception
CSyntaxError occurs due to debugger statement
DExecution pauses at the debugger line before returning the sum
Step-by-Step Solution
Solution:
  1. Step 1: Understand debugger statement effect

    The debugger; statement causes the debugger to pause execution at that line when running under a debugger.
  2. Step 2: Analyze program flow

    Running node inspect pauses at the debugger; line inside add before returning the sum, allowing inspection.
  3. Final Answer:

    Execution pauses at the debugger line before returning the sum -> Option D
  4. Quick Check:

    Debugger statement pauses execution under debugger [OK]
Quick Trick: Debugger statement pauses code only when debugger runs [OK]
Common Mistakes:
  • Thinking debugger statement causes syntax error
  • Assuming program runs without pause under debugger
  • Confusing debugger statement with console.log

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions
More Node.js Quizzes