Question

You need to execute script.sh with arguments ['arg1', 'arg2'] using execFile and separately capture both standard output and error output. Which code snippet correctly achieves this?

Accepted Answer

execFile('./script.sh', ['arg1', 'arg2'], (error, stdout, stderr) => {
  if (error) {
    console.error('Error:', error);
  }
  console.log('Output:', stdout);
  console.error('Error Output:', stderr);
});

Answer

execFile('./script.sh', ['arg1', 'arg2'], (error, output) => {
  console.log('Output:', output);
});

Answer

execFile('./script.sh', (error, stdout, stderr) => {
  console.log(stdout, stderr);
});

Answer

execFile('./script.sh', ['arg1', 'arg2'], (error) => {
  if (error) throw error;
});

You need to execute script.sh with arguments ['arg1', 'arg2'] using execFile and separately capture both standard output and error output. Which code snippet correctly achieves this?

Step 1: Use correct execFile signature

Step 2: Handle outputs separately

Final Answer:

Quick Check:

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