Which of the following is the correct way to invoke execFile with a callback to handle the output in Node.js?

easy📝 Syntax Q3 of 15

Node.js - Child Processes

Which of the following is the correct way to invoke execFile with a callback to handle the output in Node.js?

AexecFile('myProgram', ['arg1'], (error, stdout, stderr) => { /* handle output */ });

BexecFile('myProgram', (error, stdout) => { /* handle output */ });

CexecFile('myProgram', ['arg1'], (stdout, stderr) => { /* handle output */ });

DexecFile('myProgram', ['arg1'], error => { /* handle output */ });

Step-by-Step Solution

Solution:

Step 1: Review execFile signature
The correct signature is execFile(file, args, callback) where callback receives (error, stdout, stderr).
Step 2: Analyze options
execFile('myProgram', ['arg1'], (error, stdout, stderr) => { /* handle output */ }); correctly uses the callback with three parameters. execFile('myProgram', (error, stdout) => { /* handle output */ }); misses the args array. execFile('myProgram', ['arg1'], (stdout, stderr) => { /* handle output */ }); has wrong callback parameters order. execFile('myProgram', ['arg1'], error => { /* handle output */ }); only passes error.
Final Answer:
execFile('myProgram', ['arg1'], (error, stdout, stderr) => { /* handle output */ }); -> Option A
Quick Check:
Callback signature is (error, stdout, stderr) [OK]

Quick Trick: Callback receives error, stdout, stderr in that order [OK]

Common Mistakes:

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