[Solved] Identify the bug in this circuit breaker pseudocode:if breaker.state == 'OPEN': call_service() else: try: call_service() except: breaker.state = 'OPEN' | Microservices

Microservices - Resilience Patterns

Identify the bug in this circuit breaker pseudocode:

if breaker.state == 'OPEN':
  call_service()
else:
  try:
    call_service()
  except:
    breaker.state = 'OPEN'

AIt does not handle CLOSED state properly

BIt never changes state to HALF-OPEN

CIt does not reset failure count on success

DIt calls service when state is OPEN, should fail fast

Step-by-Step Solution

Solution:

Step 1: Analyze behavior when state is OPEN
The code calls the service even when breaker is OPEN, which defeats fail fast purpose.
Step 2: Identify correct OPEN state action
In OPEN state, calls should be blocked or failed immediately, not forwarded.
Final Answer:
It calls service when state is OPEN, should fail fast -> Option D
Quick Check:
OPEN state must fail fast, not call service [OK]

Quick Trick: OPEN state must not call service, fail fast instead [OK]

Common Mistakes:

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