[Solved] What will be printed by this code snippet?breaker = CircuitBreaker(state='OPEN', failureCount=3, failureThreshold=3) # After timeout breaker.state = 'HALF-OPEN' try: call_service() breaker.... | Microservices

Microservices - Resilience Patterns

What will be printed by this code snippet?

breaker = CircuitBreaker(state='OPEN', failureCount=3, failureThreshold=3)
# After timeout
breaker.state = 'HALF-OPEN'
try:
  call_service()
  breaker.state = 'CLOSED'
  breaker.failureCount = 0
except:
  breaker.state = 'OPEN'
print(breaker.state)

Assuming call_service() succeeds.

ACLOSED

BHALF-OPEN

CFAILED

DOPEN

Step-by-Step Solution

Solution:

Step 1: Understand state transition on success in HALF-OPEN
When in HALF-OPEN, a successful call resets the breaker to CLOSED and failureCount to zero.
Step 2: Check final state after successful call
Since call_service() succeeds, breaker.state becomes CLOSED.
Final Answer:
CLOSED -> Option A
Quick Check:
Success in HALF-OPEN resets to CLOSED [OK]

Quick Trick: Success in HALF-OPEN resets breaker to CLOSED [OK]

Common Mistakes:

MISTAKES

Leaving state as HALF-OPEN after success
Assuming state stays OPEN after success
Confusing failureCount reset timing

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What will be printed by this code snippet?

Step 1: Understand state transition on success in HALF-OPEN

Step 2: Check final state after successful call

Final Answer:

Quick Check:

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