Given this pseudocode snippet, what will be the output if the circuit breaker is CLOSED and the service call fails twice?

Given this pseudocode snippet, what will be the output if the circuit breaker is CLOSED and the service call fails twice?

breaker = CircuitBreaker(state='CLOSED', failureCount=0, failureThreshold=3)
for i in range(2):
  try:
    call_service()
  except:
    breaker.failureCount += 1
if breaker.failureCount >= breaker.failureThreshold:
  breaker.state = 'OPEN'
print(breaker.state)