[Solved] What will be displayed when running the following code?import seaborn as sns import matplotlib.pyplot as plt sns.lineplot(x=[0,1,2], y=[3,2,1]) plt.ylabel('Values') plt.show() | Matplotlib

Matplotlib - Seaborn Integration

What will be displayed when running the following code?

import seaborn as sns
import matplotlib.pyplot as plt

sns.lineplot(x=[0,1,2], y=[3,2,1])
plt.ylabel('Values')
plt.show()

AA scatter plot with y-axis labeled 'Values' and default x-axis label

BA line plot with y-axis labeled 'Values' and default x-axis label

CA line plot with both x and y axes labeled 'Values'

DAn error because plt.ylabel() is used incorrectly

Step-by-Step Solution

Solution:

Step 1: Understand sns.lineplot()
Seaborn's lineplot creates a line graph connecting points.
Step 2: Check axis labeling
plt.ylabel('Values') sets the y-axis label; x-axis label remains default.
Final Answer:
A line plot with y-axis labeled 'Values' and default x-axis label -> Option B
Quick Check:
Line plot + y-label only [OK]

Quick Trick: sns.lineplot creates line graphs; plt.ylabel sets y-axis label [OK]

Common Mistakes:

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What will be displayed when running the following code?