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Identify the issue in this MATLAB code:

medium📝 Debug Q6 of 15
MATLAB - Numerical Methods
Identify the issue in this MATLAB code:
f = @(t,y) 3*y;
[t,y] = ode45(f, 0:0.2:1, 1);
disp(y(end));
AIncorrect function handle syntax
BUsing a vector for time span instead of a two-element interval
CInitial condition should be a vector
DMissing semicolon after function definition
Step-by-Step Solution
Solution:
  1. Step 1: Check time span input

    ode45 expects the time span as a two-element vector [t0 tf], not a vector of points.
  2. Step 2: Analyze given code

    The code uses 0:0.2:1 which is a vector of multiple points, causing an error or unexpected behavior.
  3. Step 3: Confirm other parts

    Function handle and initial condition are correct.
  4. Final Answer:

    Using a vector for time span instead of a two-element interval -> Option B
  5. Quick Check:

    Time span must be [start end] [OK]
Quick Trick: Time span must be two-element vector [OK]
Common Mistakes:
  • Passing vector of time points instead of interval
  • Confusing function handle arguments
  • Assuming initial condition must be vector

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