[Solved] Given this pseudocode for a shared counter increment:lock.acquire() counter = counter + 1 lock.release()What happens if lock.release() is missing? | LLD

LLD - Advanced LLD Concepts

Given this pseudocode for a shared counter increment:

lock.acquire()
counter = counter + 1
lock.release()

What happens if lock.release() is missing?

AOther threads may never access the counter again

BThe counter increments twice

CThe program crashes immediately

DThe lock automatically releases after increment

Step-by-Step Solution

Solution:

Step 1: Understand lock usage
lock.acquire() locks the resource; lock.release() frees it for others.
Step 2: Analyze missing release effect
If release is missing, the lock stays held, blocking other threads indefinitely.
Final Answer:
Other threads may never access the counter again -> Option A
Quick Check:
Missing release = blocked threads [OK]

Quick Trick: Always release locks to avoid thread blocking [OK]

Common Mistakes:

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